Coding Java "Fungsi"

Selamat mencoba :)

import java.io.*;
class fungsi
{public static void main(String[] args) throws Exception{
BufferedReader input=new BufferedReader(new InputStreamReader(System.in));
int n=0;
int i;
int k=0;
System.out.print("masukan banyak relasi:");
int x=Integer.parseInt(input.readLine());
int dmn []=new int[x];
int range []=new int[x];
for(i=0;i {
System.out.print("masukan domain ke-"+(i+1)+": ");
dmn[i]=Integer.parseInt(input.readLine());
System.out.print("masukan range ke-"+(i+1)+": ");
range[i]=Integer.parseInt(input.readLine());}

System.out.print("domain={");
for(i=0;i {
System.out.print(dmn[i]);
if(i!=x-1)
{
System.out.print(",");}

}
System.out.println("}");
System.out.print("range={");
for(i=0;i {
System.out.print(range[i]);
if(i!=x-1)
{
System.out.print(",");}

}
System.out.println("}");
for(i=0;i {if(dmn[i]==dmn[i+1]){
n=n+1;}
if (range[i]==range[i+1]){
k=k+1;}
i=i+1;}
System.out.println("fungsinya :");
for(i=0;i {System.out.println("("+dmn[i]+","+range[i]+")");
if (n!=0){
System.out.println("relasi tetapi bukan fungsi");}
else{
System.out.println("relasi dan juga fungsi");}
if (k!=0){
System.out.println("fungsi tetapi bukan satu-satu");
System.out.println("fungsi onto");}
else{
System.out.println("fungsi satu-satu");}}}}


Jangan lupa coment-nya yah :)